ACboy has N courses this term, and he plans to spend at most M days on study.Of course,the profit he will gain from different course depending on the days he spend on it.How to arrange the M days for the N courses to maximize the profit? 

Input

The input consists of multiple data sets. A data set starts with a line containing two positive integers N and M, N is the number of courses, M is the days ACboy has. 
Next follow a matrix A[i][j], (1<=i<=N<=100,1<=j<=M<=100).A[i][j] indicates if ACboy spend j days on ith course he will get profit of value A[i][j]. 
N = 0 and M = 0 ends the input. 
Output

For each data set, your program should output a line which contains the number of the max profit ACboy will gain. 
Sample Input

2 2
1 2
1 3
2 2
2 1
2 1
2 3
3 2 1
3 2 1
0 0

Sample Output

3
4
6题目大意：先输入n，m代表n个课程和有m天，在输入n*m的矩阵，分别代表经历j天在i课程上，得到的一个权值，求大的权值。

#include <iostream>
#include <cstring>
using namespace std;
int a[105][105],dp[105];
int n,m;
int main()
{
    while(cin>>n>>m,n||m)
    {
        memset(dp,0,sizeof dp);
        for(int i=1;i<=n;i++)
            for(int j=1;j<=m;j++)
                cin>>a[i][j];
        for(int i=1;i<=n;i++)
            for(int j=m;j>=1;j--)
                for(int k=1;k<=j;k++)///枚举在i课程的天数
                    dp[j]=max(dp[j],dp[j-k]+a[i][k]);
        cout<<dp[m]<<'\n';
    }
    return 0;
}